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Question: What is the concavity of (x)/(x-1)?

Write down the expression as

y = x/(x-1)

y is the curve

y', or dy/dx is the slope of the curve

y'', or d^2y/dx^2 is a measure of the concavity of the curve.

y'' > 0 shows that the curve is concave upwards.

y'' < 0 shows that the curve is concave downwards.

We have y = x/(x-1), then

y' = -1/(x-1)^2

y'' = 2/(x-1)^3

Now y'' > 0 for (x-1) > 0, i.e. x > 1

And y'' < 0 for (x-1) < 0, i.e. x < 1

Answer: y(x) is concave up for x > 1, and concave down for x < 1

by Level 11 User (81.5k points)

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