how do I solve (x-3)(x-6i)(x+6i)

find the polynomial of lowest degree having real coefficients, a leading coefficient of 1, with a zero of 3 (multiplicity 2) and a zero of 6i
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1 Answer

(x-6i)*(x+6i)=x^2 -(6i)^2....x^2+36

yer job=multipli that bi (x-3)
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