Solve the following equation. please show all of your work. 3-6/7x=21

Question

how to I solve this showing all work?

Answer 1

3 - 6/7x = 21 first we must get x by itself, to this we subtract 3 from both sides

3-3-6/7x= 21-3 the 3's on the left side cancel out

-6/7x = 18 next multiply both sides by 7

7(-6/7)=18(7) the 7's cancel out because when you cross multiply, 7 goes into 7 once.

-6x = 126 now divide each side by -6, since it is being multiplied by x you divide to undo that.

-6/-6x = 126/-6     -6/-6 is just 1

1x = -21

x =- 21

Answer 2

3-6/7x=21

take   LCM for the left hand side of the equation

3(7x)  -  6     / 7x       =   21          ( transposition 7x)

21x    -   6    =  21(7x)

21x     -   6   =   147 x

21x   -  147 x    =  6

-  126  x   =   6

x   =  6  /  -126

=   -1  / 21