How do you solve (8x+1) + (3x-2) = 32

Question

Please help me solve this problem.

Answer 1

How do you solve (8x+1) + (3x-2) = 32
Please help me solve this problem.

(8x + 1) + (3x - 2) = 32
8x + 1 + 3x - 2 = 32
11x - 1 = 32
11x = 33
x = 3

Answer 2

Hello! Try this solution;

(8x + 1) + (3x - 2) = 32
8x + 1 + 3x - 2 = 32

8x + 3x + 1 - 2 = 32

11x - 1 = 32

11x = 32 + 1

11x = 33

x = 33/11

x = 3;

Answer 3

Simplifying
2x + 140 = 4x + 16

Reorder the terms:
140 + 2x = 4x + 16

Reorder the terms:
140 + 2x = 16 + 4x

Solving
140 + 2x = 16 + 4x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-4x' to each side of the equation.
140 + 2x + -4x = 16 + 4x + -4x

Combine like terms: 2x + -4x = -2x
140 + -2x = 16 + 4x + -4x

Combine like terms: 4x + -4x = 0
140 + -2x = 16 + 0
140 + -2x = 16

Add '-140' to each side of the equation.
140 + -140 + -2x = 16 + -140

Combine like terms: 140 + -140 = 0
0 + -2x = 16 + -140
-2x = 16 + -140

Combine like terms: 16 + -140 = -124
-2x = -124

Divide each side by '-2'.
x = 62

Simplifying
x = 62