how do you solve long division polynomial

(9b^2+9b-10) / (3b-2)
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1 Answer

(9b^2+9b-10) / (3b-2) = 3B + 5

                        3b + 5

                       -------------------------------                    3b*3b = 9b^2

3b - 2                9b^2 + 9b - 10                                   3b(-2) = - 6b

                         9b^2 - 6b

                       -         +

                     -----------------------------                          3b*5 = 15b

                                  15b - 10                                    -2*5 = - 10

                                   15b - 10

                                  -       =

                                 ----------------------

                                         0

                      

by Level 8 User (36.8k points)

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