1.      2csc2 A – 32

2.      3cot2 B – 27

3.      Sin2 Ө – 18sin Ө + 81

4.      5cos3 w – 15

5.      Cot3 Ө + 2cot2 Ө + cot Ө

 

 

So this is Factoring trigonometric functions

 

Anyone who knows how to solve this?

MANY MANY MANY MANY MANY thanks to anyone who can solve this. 

in Trigonometry Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

 2csc2 A – 32 =                  3cot2 B – 27 =

                                         3(cot^2 - 9)=

(2csc^2 - 32) =                 3( cot^2 - 3^2)

2(csc^2 - 16 )=                3( cot - 3)( cot + 3)

2(csc^2 - 4^2) =

2(csc - 4)( csc + 4)

 

Sin2 Ө – 18sin Ө + 81 = ( sin - 9)( sin - 9)

5cos3 w – 15 = 5(cos^3 - (3^(1/3))^3=

5(cos - 3)( cos^2  + 3^(1/3)*cos + 3^(1/3)^2 )

by Level 8 User (36.8k points)
Thank you so much sir! :)

Related questions

1 answer
1 answer
asked Oct 20, 2011 in Trigonometry Answers by anonymous | 697 views
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,550 questions
99,628 answers
2,417 comments
440,451 users