how to factorise 2x^2+10x-8

i have to factorise this quadratic equation- 2x^2+10x-8
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1 Answer

2x^2+10x-8=0...become x^2+5x-4=0

become (x-0.701562119)*(x+5.701562119)

b^2-41c=41, sqrt(41)=6.403124237
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