0=1/2*-4.905t^2+1.85t+69.3

How do I solve 0=1/2*-4.905t^2+1.85t+69.3
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1 Answer

(1/2)*(-4.905x^2 +1.85x+69.3=0

become -2.4525x^2 +1.85x+69.3=0

or +2.4525x^2 -1.85x -69.3=0

quadratik equashun giv roots=5.706250041 & -4.951917727

-b/2a=0.377166157

b^2-4ac=683.2555, sqrt=26.139156452, root/2a=5.329083884
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