∑[i=0,∞,(1)/(4^(i))]

or

infinity

Sigma 1/4^i

i = 0

Thank you for any assistance

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1 Answer

This is the series S=1/40+1/41+1/42+1/43+... , which is a geometric progression.

S/4=1/41+1/42+1/43+...

S-S/4=¾S=1. 1/4i→0 as i→∞, so S=4/3 or 1⅓.

by Top Rated User (1.1m points)

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