5 red, 7 blue and 8 green marbles.....

5 red, 7 blue and 8 green marbles. Two drawn consecutively and without replacement. Probability of neither being blue?
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The chance of drawing no blue marbles on the first draw is 13/20 and the chance of drawing from the 12 remaining non-blue marbles on the second draw is 12/19. So the chance of neither being blue is 13/20*12/19=39/95=0.4105 or 41.05% approx.

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