f(x, y) = x2 + xy + y2 + 2x - y ; (-3, 1)

What are the answers for f(sub(x))(-3,1) and  f(sub(y))(-3,1)
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1 Answer

Given f(x, y) = x^2 + xy + y^2 + 2x - y
(x,y) =(-3, 1)
f(-3,1)=(-3)^2 + (-3)(1) + 1^2 + 2(-3) - 1
f(-3,1)=0

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by Level 8 User (30.1k points)

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