The equation that is being solved is f(x)=2^2x-8x-3

 

written in f(x)=a(x-h)^2+k
in Algebra 1 Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

This question has already been answered. Here's the solution again.
I think the equation should be f(x)=2x^2-8x-3. We can write this: 2(x^2-4x)-3. The expression in parentheses needs to be converted to a perfect square. We do this by halving the coefficient of the x term and then squaring it. (4/2)^2=4, so the expression becomes x^2-4x+4=(x-2)^2. But we have to adjust -3 to compensate for the number we just added. 2(x-2)^2=2x^2-8x+8 so we need to subtract the 8 we added and combine it with -3 making it -11. So f(x)=2(x-2)^2-11, the standard parabolic form. Quick check: when x=0, f(x)=-3.
by Top Rated User (1.1m points)

Related questions

1 answer
2 answers
1 answer
1 answer
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,804 answers
2,417 comments
522,420 users