Question 1: (x-3)(x^2+4x+5) and Question 2: (x+1)(2x-1)(x+3)

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Question 1: (x-3)(x^2+4x+5)

Question 2: (x+1)(2x-1)(x+3)

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1 Answer

Question 1

(x-3)(x^2+4x+5)=x(x^2+4x+5)-3(x^2+4x+5)=x^3+4x^2+5x - 3x^2-12x-15=

x^3+(4-3)x^2+(5-12)x-15=x^3+x^2-7x-15.

Question 2

(x+1)(2x-1)(x+3)=(x+1)(2x(x+3)-(x+3))=(x+1)(2x^2+6x-x-3)=(x+1)(2x^2+(6-1)x-3)=(x+1)(2x^2+5x-3)=

x(2x^2+5x-3)+(2x^2+5x-3)=2x^3+5x^2-3x+2x^2+5x-3=2x^3+(5+2)x^2+(-3+5)x-3=

2x^3+7x^2+2x-3.
by Top Rated User (1.1m points)

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