how do i graph 8x+3y+24=0 on a graph

Question

There is no other infomation.

Answer 1

Make the equation into slope-intercept form (y = mx + b)

 

8x+3y+24=0

8x+3y = -24

3y = -8x - 24

y = -8/3x - 8 (This is our answer)

Go to the orgin of the graph (0,0), down 8 units (this is call y-intercept; (0,8)). From (0,8) move down 8 units, then to the left 3 units. This is your slope; -8/3x.

The graph should look like a line from top left to bottom right.