How do you find the critical values for this function?
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1 Answer

y=x^4+4x^3+8x^2 become x^2*(x^2+4x+8)

x^2 tell yu y=0 at x=0

for x^2+4x+8, yuze quadratik equashun tu find zeroes

get zeroes=-2+-2i  (komplex variabels)

b^2-4ac=-16, so sqroot=+-4i

-b/2a=-2
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