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Equation of a circle of radius r and centre (h,k):

(x-h)2+(y-k)2=r2, so we can now plug in the given points:

(4-h)2+(2+k)2=r2, (8-h)2+(10+k)2=r2, (1+h)2+(7+k)2=r2.

 (4-h)2+(2+k)2=(8-h)2+(10+k)2,

16-8h+h2+4+4k+k2=64-16h+h2+100+20k+k2,

20-8h+4k=164-16h+20k,

8h-16k=144, h-2k=18, (1) h=2k+18

(8-h)2+(10+k)2=(1+h)2+(7+k)2,

64-16h+h2+100+20k+k2=1+2h+h2+49+14k+k2,

164-16h+20k=2h+14k+50,

18h-6k=114, (2) 3h-k=19

3(2k+18)-k=19, 6k+54-k=19, 5k=-35, k=-7, so h=-14+18=4.

Plug (h,k) into (1+h)2+(7+k)2=r2:

52+0=r2, so r=5 and the equation of the circle is (x-4)2+(y+7)2=25.

by Top Rated User (1.1m points)

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