find integral (x^3)/(x^2+8)

find integral (x^3)/(x^2+8)
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1 Answer

x3/(x2+8)=x-8x/(x2+8).

∫(x-8x/(x2+8))dx=∫xdx-4∫2xdx/(x2+8)=x2/2-4ln|x2+8|+C, where C is integration constant.

by Top Rated User (1.1m points)

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