How high above the surface is the ring?

Question

Imagine a perfectly smooth sphere about the size of the planet Saturn and imagine a thin rigid circular ring around the sphere's equator. Now, suppose you add one foot to the length of the ring and place it around the equator again so that it is the same distance all round from the sphere's surface. What is the height above the surface? The answer may surprise you! (Take pi=3.14.)

Answer 1

distans round serkel inkreez bi 1 foor...

distans around=2*pi*radius

thus, delta-radius=(1 foot)/(2pi)

2pi=6.2831853071795864769252867665590057...

1/2pi=0.15915494309189498=chaenj in radius av the serkel