find the intercepts with the axes or asyptotes, and draw a sketch of: y=(6/x)
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There are no intercepts, because the equation is not defined when either x or y is zero.

However, the axes are asymptotes for the hyperbolic curve. For example, when x or y is 1 y or x is 6. For x or y is 12, y or x is 1/2. For x or y = 48, y or x is 1/8. So when x and y get large and positive, the curve comes closer to each axis. The same happens by reflection for negativity be values. Now the graph can be drawn. In the 1st quadrant and 3rd quadrants we can see the hyperbolas. There is no curve in quadrants 2 and 4. So the hyperbolas have a sort of L or an inverted L shape in quadrants 1 and 3, with a curve between 0 and 1, and 0 and -1, for x and y joining the vertical part of the L to the horizontal part.

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