determine the following integrals: [2pie cos(ax+b) + 3^2x] dx

Note it is often necessary to simplify the integrand first
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Integral = I = I ( 2piecos(ax+b) + 3^2x)dx

2pie* I (cos(ax+b)dx + I (9^x)dx=

ax+b = u

adx = du

dx = du/a

2pie*I (cosu)du/a  + I(9^x)dx =

2piesinu/a + 9^x/ln9 + C=

(2pie/a)sin(ax+b) + 9^x/lnx + C
by Level 8 User (36.8k points)

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