I need to know the instructions of this function as in what it does in words.
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(2t-3)/(t+2).

As t approaches -2 the function approaches infinity, so t=-2 is a vertical asymptote which is a vertical line that the curve never quite touches but to which it gets closer and closer the nearer t is to -2 (approaching from either side of -2, that is, just less than -2 or just greater than -2.

We can also see that when 2t-3=0, that is, when t=3/2 the value of the function is zero, which makes it the t-intercept.

We can also see that when t is large and positive the constants become insignificant and the function approaches 2t/t=2. It also approaches 2 when t is large and negative. Since the vertical axis is the function value we can draw a horizontal line 2 units above the horizontal t-axis (horizontal asymptote). The function never quite touches this line as t increases in magnitude.

So we have a vertical line at t=-2 and a horizontal line at f(t)=2 (where f stands for function). These lines divide the plane into four sections like a very large window with one horizontal bar and one vertical bar, dividing the window into four panes. The top left pane encloses one part of the curve completely separated from the other part which is enclosed in the bottom right pane, which includes the part of the curve that crosses the t-axis at t=3/2. When t=0, f(0)=-3/2, which is the vertical intercept, where the curve crosses the vertical axis in the bottom right pane.

ago by Top Rated User (1.1m points)

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