If 2^x + 2^y = 8 and 3^x + 3^y =18 then find the value of x and y

Question

I want to know how to solve this.

Answer 1

2^x+2^y=8

take log tu base 2...x+y=log2(8)=3

then 3^x+3^y=18..take log tu base 3 & yu get x+6=loe3(18)

=2.630929753571457

but sumthun rong, kauz yu now hav x+k6=2.630929753571457

Answer 2

2^x+2^y=8=2^3; 3^x+3^y=2*3^2.

The second equation seems to hold the clue because there are two terms on the left and if they are equal we have 2*3^x=2*3^2, and x=2 so y=2. Now we turn to the first equation: 2*2^x=2*2^2, so x=y=2; therefore the solution is x=y=2.