I know that distance equals rate times time. I just can't figure out how to set up the equation to solve it.
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2 Answers

delta=15-9=6

river speed=6/2=3
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Let the speed of the boat be B. Let the speed of the water be W.

When the boat goes against the current upstream the combined speed is B-W and when the boat goes with the current downstream it's B+W. (distance)=(speed)(time) so (time)=(distance)/(speed). These quantities are equal so we can write 9/(B-W)=15/(B+W). Cross multiply: 9(B+W)=15(B-W), so 9B+9W=15B-15W; 24W=6B so W=B/4. Plug in B=16mph and we get W=4mph.

CHECK: Time to go upstream=9/12=time to go downstream=15/20. Both fractions are 3/4. So it checks out (3/4 hr).

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