Using The Bionomial Thereom What Is The Third Term For (x-2)^12.
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(A+B)^12=A^12+12A^11B+((12)(11)/2)A^10B^2+... If A=x and B=-2:

(x-2)^12=x^12-(12)x^11*2+66x^10(2^2)-...

So third term is 264x^10.
by Top Rated User (1.1m points)

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