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Let the number be 10a+b. So a+b=13, a=13-b; 10a+b=7b+2, 10a=6b+2, 5a=3b+1. So 5(13-b)=3b+1, 65-5b=3b+1, 8b=64, b=8, and a=5. The number is 58.

by Top Rated User (1.1m points)
In ordinary numerical digits, what is 67 more than the sum of the two-digit numbers s.i._x___s.i._x and .e._i_g.h.t___n._i.n_e?
by Level 1 User (180 points)

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