solve the following equations b) (2-3j)=(a+jb)^0.5

this under complex number, may you please expalin to me the steps on how to solve it
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1 Answer

We square both sides:

(2-3j)(2-3j)=a+jb; 4-12j+9j^2=a+jb.

But j^2=-1 by definition of j, so 4-12j-9=a+jb. Therefore, -5-12j=a+jb.

Equating real and imaginary:

a=-5 and b=-12.
by Top Rated User (1.1m points)

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