Problem: how do you solve 3(y+3)=4(y-2)
how do you solve 3(y+3)=4(y-2)
3(y + 3) = 4(y - 2)
3y + 9 = 4y - 8
3y + 9 - 4y = 4y - 8 - 4y
-y + 9 = -8
-y + 9 - 9 = -8 - 9
-y = -17
y = 17
Check.
3(y + 3) = 4(y - 2)
3(17 + 3) = 4(17 - 2)
3(20) = 4(15)
60 = 60
Answer: y = 17