Prove that the quadrilateral that is formed by joining the midpoints of the sides of a square is a square.

(Theorem : The straight line segment through the midpoints of two sides of a triangle is parallel to the third side and equal in length to half of it.)

in Geometry Answers by Level 2 User (1.7k points)

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Best answer

Imagine the square has side length 2a. The midpoints of the sides are length a from each corner and the hypotenuses of the right-angled triangles at each corner all have the same length a√2. The quadrilateral is therefore a rhombus. The right-angled triangles at the corners are isosceles making the angle between each hypotenuse and each side 45 degrees. The interior angles of the rhombus is 180-45-45=90 degrees, so the rhombus is a square.

by Top Rated User (1.1m points)
selected by

Related questions

1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,804 answers
2,417 comments
522,463 users