Three friends, Bob, Chuck, and Dan take turns (in that order) throwing a die until the first “six” appears.

Question

it is the question of probiblity.book nnae fundamental of applied probabilty 3rd edition.

Answer 1

No specific question has been given.

Probability of Bob throwing the first six is 1/6=16.67%

Probability of Chuck doing so is 5/6*1/6=5/36=13.89%

Probability that Dan throws the first six is 5/6*5/6*1/6=25/216=11.57%

Probability that none throws a six is 57.87%

16.67+13.89+11.57+57.87=100%