(-3) to the power of 6 divided by (-3) to the 8th power

Question

i need to divide the quantity of negative three to the sixth power by the quantity of negative three to the 8th power

Answer 1

Because the same number (-3) is being raised to different powers, just subtract the powers when dividing: (-3)^6/(-3)^8=(-3)^(6-8)=(-3)^-2=1/(-3)^2=1/(-3)(-3)=1/9.