if ab = 6 feet, ad= 2 feet, and m<dae = 65, find bc

Question

it has a picture with it, but it can be solved without the picture

Comments

I really think we need the picture because we don't know what shape we're dealing with.

Answer 1

 

The picture shows a trapezium with the given sides and angle marked according to the question.

Angle ACB=DAE=65 (alternate angles between parallel lines EA and CB).

DB=√(6^2-2^2)=√32=4√2 (Pythagoras).

DB/BC=sin65, so BC=4√2/sin65=6.24 ft approx.

This is one possible solution under the assumed pictured figure.