Triangle ABC has the following measurements: AB = 12cm, BC = 8cm, AC = 14 cm. Find the height BE on the side AC, and the area of the triangle.
asked Dec 13, 2016 in Geometry Answers by anonymous

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Let BE=h and CE=x, so EA=14-x. We have two right-angled triangles back to back: ABE and BCE.

By Pythagoras h^2+x^2=64 and h^2+(14-x)^2=144, or h^2+x^2-28x+196=144.

But h^2+x^2=64 from the first equation, so 64-28x+196=144 and 28x=64+196-144=116.

Therefore x=116/28=29/7. So we can find h=√(64-(29/7)^2)=6.8437cm approx.

The area of the triangle is (1/2)14h=47.9062 sq cm approx.

answered Dec 13, 2016 by Rod Top Rated User (429,320 points)

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