Every weekend, you ride your bicycle on a forest preserve path that is 20 miles long and ends at a waterfall where you relax and then make the trip back to the starting point, and you find that in the same time it takes you to travel to the waterfall, you are only able to return 14 miles, so your average speed going to the waterfall is 3mph faster than the return trip, so what was your average sped going to the waterfall?
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3 Answers

Every weekend, you ride your bicycle on a forest preserve path that is 20 miles long and ends at a waterfall where you relax and then make the trip back to the starting point, and you find that in the same time it takes you to travel to the waterfall, you are only able to return 14 miles, so your average speed going to the waterfall is 3mph faster than the return trip, so what was your average sped going to the waterfall?

We need to find average speed going to the waterfall.

We are given that we can travel 20 miles with that speed in the same amount of time that it will take us to travel 14 miles at the return speed. Also, speed to the waterfall = return speed +3mph.

Time = distance/ Rate, so set the 2 equations equal to each other and solve

Let r = rate of speed to the waterfall.

20/r = 14/r-3

r = 10mph to waterfall

return from waterfall is 7mph.

 

 

 

 

by Level 6 User (19.3k points)
5 divided by 4,820
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You just have to do long division! it will help!
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