The age of mrs. Laurel is 9 years more than 3 times her aon's age. Find the age of each if fifteen years from now she will be 6 years more than twice her son's age.

Question

How to solve the eqution. What is the process?

Answer 1

The age of mrs. Laurel is 9 years more than 3 times her son's age. Find the age of each if fifteen years from now she will be 6 years more than twice her son's age.

Let L = mrs Laurel's current age

Let S = the son's current age

L = 3S + 9        (mrs. Laurel is 9 years more than 3 times her son's age

​L + 15 = 2(S + 15) + 6       (fifteen years from now she will be 6 years more than twice her son's age.

Substituting for L = 3S + 9 into teh 2nd equation,

3S + 9 + 15 = 2S + 30 + 6

S + 24 = 36

S = 12

L = 3S + 9 = 36 + 9 = 45

The ages are: Mum = 45, Son = 12