d^2A/dt^2-4dA/dt-5A=0

Differentiation of vectors
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1 Answer

d^2A/dt^2-4dA/dt-5A=0

auxiliary equation

m^2 - 4m - 5 = 0

(m + 4)(m - 5) = 0

m1 = -4, m2 = 5

Solution is: y(x) = A.e*(-4x) + B.e^(5x)

by Level 11 User (81.5k points)

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