in a city there are three daily newspapers A, B and C.  42% people read A.  51% read B and 68% read C.

36% read A and C.  28% read B and C. 30% read A and B. 8% dont read any newspaper.  Find percentage of persons who read all the three newspapers
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In above Venn diagram the letters label regions identified as follows:

All the numbers are percentages.

A Non-readers (8)

B Read newspaper A only

C Read newspaper B only

D Read newspaper C only

E Read A and C only 

F Read B and C only 

G Read A and B only 

H Read all three newspapers

A+B+C+D+E+F+G+H=100 (all the people)

B+C+D+E+F+G+H=100-8=92

B+E+G+H=42 (A readers); 

C+F+G+H=51 (B readers)

D+E+F+H=68 (C readers)

We have to interpret the statement: 36% read A and C. This could mean they (a) Read A and C only or (b) Read A and C and possibly B. Similarly with the 28% reading B and C and the 30% reading A and B.

If we look at (a) first, this implies that E+G=30+36=66; but E+G+B+H=42, so B+H=-24, which cannot be since all the percentages have to be positive. So interpretation (b) is the acceptable one. This means that:

(E+H)+(G+H)=E+G+2H=30+36=66 and E+G=66-2H, so:

E+G+B+H=42=66-2H+B+H=66+B-H.

Therefore H-B=24 or B=H-24. Now we have B and E+G in terms of H.

Similarly, (E+H)+(F+H)=E+F+2H=36+28=64 and E+F=64-2H, so:

E+F+D+H=68=64-2H+D+H=64+D-H.

Therefore 4=D-H or D=H+4.

And (F+H)+(G+H)=F+G+2H=58 and F+G=58-2H, so:

F+G+C+H=51=58-2H+C+H=58+C-H.

Therefore H-C=7 or C=H-7.

Substituting for the variables that we have in terms of H, we can write:

(E+G)+(E+F)+(F+G)=66-2H+64-2H+58-2H=188-6H=2(E+F+G); E+F+G=94-3H.

B+C+D=H-24+H-7+H+4=3H-27 so B+C+D+E+F+G+H=3H-27+94-3H+H=92.

H=92-94+27=25, so 25% of the people read all three newspapers.

by Top Rated User (1.1m points)

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