two years ago my age was four times that of my son eight years ago my age was ten times that of my son.find the age of my son
Let S be the current age of my son.
Let M be the current age of me.
(M - 2) = 4(S - 2) (two years ago my age was four times that of my son)
(M - 8) = 10(S - 8) (eight years ago my age was ten times that of my son)
Simplifying the above two equations gives us,
M - 4S = -6
M - 10S = -72
Subtracting 2nd eqn from 1st,
6S = 66
S = 11
M = 4S - 6 = 44 - 6 = 38
Our current ages are: Me 38 yrs, Son 11 yrs
