Thanks in advance. Please help me.
in Calculus Answers by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
Anti-spam verification:
To avoid this verification in future, please log in or register.

1 Answer

Top and bottom factorise: x^2(x+2)(x+3)/(x^2-4)(x+1)=

x^2(x+2)(x+3)/(x-2)(x+2)(x+1)=

x^2(x+3)/(x-2)(x+1).

However, when x=2 the denominator goes to zero. When x=2 the numerator goes to 20, a finite number. The limit as x approaches 2 is therefore infinity (dividing by zero).

The limit as x approaches -2 is 4/(-4)(-1)=1, and perhaps this is what the question should be. The expression has a removable anomaly which allows the limit to be evaluated when x=-2.

by Top Rated User (1.1m points)

Related questions

1 answer
1 answer
asked Sep 29, 2021 in Calculus Answers by anonymous | 898 views
1 answer
1 answer
Welcome to MathHomeworkAnswers.org, where students, teachers and math enthusiasts can ask and answer any math question. Get help and answers to any math problem including algebra, trigonometry, geometry, calculus, trigonometry, fractions, solving expression, simplifying expressions and more. Get answers to math questions. Help is always 100% free!
87,542 questions
99,806 answers
2,417 comments
523,408 users