3xy^5(2x^4y/6x^5*y^3)^-2

Question

3xy to the 5th power multiplying in parantheses 2x to the 4th times y over 6x to the fifth power times y to the third power closed parantheses all to the power of -2 in parantheses.

Answer 1

 

3xy^5(2x^4y/6x^5*y^3)^-2
= 3xy^5 ((6x^5 y^3) / (2x^4 y))^2
= 3xy^5 (3xy^2)^2
= 3xy^5 (9x^2 y^4)
= 27 x^3 y^9