what would be the end answer when you convert (-1, sqr root of 3) into polar form?
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1 Answer

x=-1, y=√3.

Conversion formulas: x=rcosθ, y=rsinθ, so r2=x2+y2=1+3=4, so r=2.

tanθ=y/x=-√3, θ=⅔π. (-1=2cos(2π/3), √3=2sin(2π/3) confirms the conversion).

Polar coords=(2,2π/3)

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