30b+53≥18b−83

Question

I need to know how to do it like the steps.

Answer 1

Don't worry! Inequalities are my thing!

30b+53≥18b−83

First since 30b and 18b are on different sides, you cobine like terms. on each side!

18b - 18b = 0 I'm putting that on the other side.

30b - 18b = 12b

So far we have 12b + 53≥-83

Now we do 53 - 53 = 0 and do that to the other side as well.

-83 - 53 = -136

Now we have 12b ≥ -136

Now in order for the b be by itself is to divide 12/12 = 0 and to the other side -136/12 = -11.333...

And for the best part ----- Answer is

                                      b ≥ -11.333...

Answer 2

Subtract 18b from each side: 12b+53≥-83

Subtract 53 from each side: 12b≥-136

Divide both sides by  4: 3b≥-34, divide both sides by 3: b≥-34/3.