How many milliliters of a 3.60 M NaBr solution contain 62.9 g of NaBr?

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Molecular weight of NaBr=23+80=103 approx.

1000ml of NaBr solution contains 103g of the solute (1 mole).

But the higher concentration means that 1000ml contains 3.60×103=370.8g of solute (3.60M).

62.9g therefore requires 62.9/370.8×1000=169.63ml, about 170ml of 3.60M molar solution.

 

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