Assuming that no parentheses are missing we have the call of a function h which has one argument. So, in other words h(x) where x is s(delta)=ln(e)+0100 >> 1. The inclusion of an equal sign suggests a logic statement. This would have one of two results: true or false, represented by the binary numbers 1 or 0, or -1 or 0. So we would have h(1) or h(-1) or h(0) where h has been previously defined as a function.
ln(e)=1. 0100 looks like a binary number (4 in decimal) and >> 1 may mean right shift (equivalent of dividing by 2). If we assume >> has a higher operational priority than +, 0100 >> 1 would represent the number 2 (4/2=2). Therefore, we would get s(delta)=1+2=3. We have to assume s is another previously defined function with a single argument. We also have to assume that delta has been previously defined, and either s(delta)=3 or s(delta)≠3. The former result is TRUE (1 or -1), otherwise it’s FALSE (0), and the result will be h(TRUE) or h(FALSE).
This is the best explanation I can come up with, but it would be helpful if we had a photo of the original equation and its context, especially definitions of what look like functions h and s.