Write the given complex number, z, in standard form: z=2-2i23/3+i14

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I read this as z=(2-2i²³)/(3+i¹⁴). If this is correct then:

i²³=(i⁴)⁵×i³=1×(-i)=-i, i¹⁴=(i⁴)³(i)²=-1 and z=(2+2i)/(3-1)=(2+2i)/2=1+i.

by Top Rated User (1.1m points)
Z=-2-5i/3-6i
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