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1 Answer

2sin²(x)=sin(x), 2sin²(x)-sin(x)=0, sin(x)(2sin(x)-1)=0.

So sin(x)=0, and x=nπ where n is an integer.

Also, sin(x)=1/2, x=π/6, 5π6, 13π/6, 17π/6, ...(12n+1)π/6, (12n+5)π/6.

by Top Rated User (1.1m points)

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