how do you solve 4^(3x+1)<28 using logs

I'm so confused on how to do this even though everyone tells me it is so easy :(
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1 Answer

4^(3x+1)<28 introduce log

thus (3x+1)log4<log28

thus 3x+1<log28/log4

3x+1<2.404

thus 3x<1.404

x<0.468

 

by Level 2 User (1.9k points)

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