EF bisects AD at C. if AC = 5x - 8 and CD = 16 - 3x. Find the value of x and AD

EF bisects AD at C. if AC = 5x - 8 and CD = 16 - 3x. Find the value of x and AD
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1 Answer

C is the mid-point of AD

Therefore we have,

AC=CD

5x-8=16-3x

5x+3x=16+8

8x=24

x=24/8

x=3

AD=AC+CD       or AD=2AC or AD=2CD

AD=5x-8+16-3x

AD=2x+8

AD=2(3)+8

AD=6+8

AD=14 units
by Level 8 User (32.3k points)

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