Find the local extreme values of the given function:

Question

local extremes

Answer 1

The given answer options are all wrong as can be seen from the graph below:

To confirm the error, we differentiate f(x):

f'(x)=4x³-12x=0 at extrema so 4x(x²-3)=0, giving us the points x=0, x=√3 and x=-√3.

f(0)=0, f(√3)=9-18=-9=f(-√3), minima at (-1.73,-9) and (1.73,-9), maximum at (0,0).

Comments

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