How many possible 3 digit numbers can be formed from these numbers

{1,2,3,4,5,6,7,8,9} if

i) Repetition is allowed?

ii) Repetition is not allowed?
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1 Answer

(i) Choice of 9 digits for each decimal place gives 9³=729 numbers.

(ii) ⁹P₃=9×8×7=504 numbers.

by Top Rated User (1.1m points)

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