Question

y = 4x² + 12x

1. With the equation, you picked above, solve for its x-intercepts… 2. Solve for the y-intercept of the equation you chose… 3. Now find the axis of symmetry (or the x - coordinate of the vertex) for your selected equation... 4. Find the y - coordinate for the vertex of your chosen equation using what you got for (#3)… 5. Using all of the information you just found, make a rough sketch of the graph for your equation on the coordinate plane given… (Scale the intervals if needed) (insert graph here)

Answer 1

(1) 4x²+12x=4x(x+3)=0, x=0, x=-3 are the x intercepts.

(2) y=0 is the y-intercept (plug x=0 into 4x²+12x).

(3) y=4(x²+3x+9/4-9/4)=4(x+3/2)²-9, the vertex is at (-3/2,-9) so the axis of symmetry is x=-3/2.

(4) y=-9

(5) Graph: